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NCERT Class 10 solution – Pairs of Linear Equations in Two Variables

NCERT Class 10 solution – Pairs of Linear Equations in Two Variables

Linear Equations Linear Equations Exercise 3.1 1. Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically. Answer Let present age of Aftab be x And, present age of daughter is represented by y Then Seven years ago, Age of Aftab = x -7 Age of daughter = y-7…

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Ncert class 10 polynomial solutions

Ncert class 10 polynomial solutions

Are you searching for class 10 chapter – 2 polynomial solutions? you’re at the right place. You can get accurate CBSE NCERT Solutions for all subjects. These solutions will help you a lot in scoring good marks in the exams. Page No: 28 Polynomial solutions – Exercises 2.1  1. The graphs of y = p(x) are given in the following figure, for some polynomials p(x). Find the number of zeroes of p(x), in each case. Answer (i) The number of…

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NCERT Class 10 Maths real number solutions

NCERT Class 10 Maths real number solutions

NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Here, we are Providing Chapter 1 Real Numbers NCERT Solutions for Class 10 Maths which will be helpful for students. These arrangements are refreshed by the 2019-20 prospectus. You can see a detailed solution as well as download pdf file too. Real number solutions Exercise 1.1 1. Use Euclid’s division algorithm to find the HCF of: (i) 135 and 225(ii) 196 and 38220(iii) 867 and 255 Answer (i) 225 >…

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NCERT Solutions Class 10 Maths Real Numbers

NCERT Solutions Class 10 Maths Real Numbers

NCERT Solutions Class 10 Maths Real Numbers CHAPTER 1 (REAL NUMBER) QUESTION-1 Use Euclid’s division algorithm to find the HCF of: i)135 and 225 ii)196 and 38220 iii)867 and 225 Solution: i) We start with the larger number i.e 225 By Euclid’s division algorithm, we have 225=1×135+90 135=1×90+45 90=2×45+0 Hence, HCF(225,135)=HCF(135,90)=HCF(90,45)=45 Therefore, the HCF of 135 and 225 is 45   ii) We start with the larger number i.e 38220 By Euclid’s division algorithm, we have 38220=196×195+0 196=196×1+0 Hence ,…

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